1.

A galvanometer of resistane G can measure 1 A current. If a shunt S is used to convert it into an ammeter to measure 10 Acurrent . The ratio ofG/Sis

Answer»

` 1/9`
`9/1 `
10
`1/10`

SOLUTION :Here , ` I_(G) = I A `
I = 10 A
Fromfigure, `I_(g)G = ( I - I_(g))S `
` G/S = (I-I_(g))/(I_(g))`
Substitutingthe GIVENVALUES, we GET
` G/S= (10 A -1 A)/( 1 A) = 9/1 `


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