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A galvanometer with coil resistance 12Omega shows full scale deflection for a current of 2.5mA. How will you convert it into an ammeter of range 0 to 7.5A. |
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Answer» SOLUTION :`S=(I_gG)/(I-I_g)=(2.5xx10^-3xx12)/(7.5-2.5xx10^-3)=4xx10^-3Omega` By connecting `4xx10^-3 Omega` resistor parallel to the GALVANOMETER we can convert it into an AMMETER of range 0-7.5A. |
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