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A game consists of tossing a 1 rupee coin three times, and nothing its outcomes each time. Find the probability of getting(i) 3 Heads,(ii) at least 2 tails. |
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Answer» When a coin is tossed three times, all possible outcomes are HHH,HHT,HTH,THH,HTT,THT,TTH and TTT. The number of total outcomes = 8. (i) The outcomes with three heads is HHH. the number of outcomes with three heads = 1 Therefore, P(getting at least two tails) = \(\frac{number\, of\,favorable\,outcomes}{number\,of \,all\,possible\,outcomes}\) = \(\frac{4}5\) = \(\frac{1}2\) Thus, the probability of getting at least two tails is \(\frac{1}2\). |
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