Given: A game of chance consists of spinning an arrow which is equally likely to come to rest pointing number 1, 2, 3 ….12

Required to find: Probability of following

Total numbers on the spin is 12

(i) Favourable outcomes i.e. to get 10 is 1

So, total number of favourable outcomes i.e. to get 10 is 1

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting a 10 = 1/12

(ii) Favourable outcomes i.e. to get an odd number are 1, 3, 5, 7, 9, and 11

So, total number of favourable outcomes i.e. to get a prime number is 6

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting a prime number = 6/12 = 1/2

(iii) Favourable outcomes i.e. to get a multiple of 3 are 3, 6, 9, and 12

So, total number of favourable outcomes i.e. to get a multiple of 3 is 4

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting multiple of 3 = 4/12 = 1/3

(iv) Favourable outcomes i.e. to get an even number are 2, 4, 6, 8, 10, and 12

So, total number of favourable outcomes i.e. to get an even number is 6

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting an even number = 6/12 = 1/2