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A gardener is watering plants at the rate 0.1 litre/sec using a pipe of cross - section 1 cm^(2). What additional force he has to exert if he desires to increase the rate of watering two times ? |
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Answer» Solution :`F=Adv^(2)=((Av)^(2)d)/(A)` If rate of watering plant (Av) is DOUBLED, it means amount of water poured / SEC is doubled which is possible only if VELOCITY is doubled. Hence force is to be made 4 times. `THEREFORE` additional force = 3 times initial force `=3 Adv^(2)=3((Av)^(2))/(A)d` `=(3xx0.1xx0.1xx10^(3))/(10^(-4))=3xx10^(5)N` |
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