1.

A garrison of 120 men has provision for 30 days. At the end of five days, five more men joined them. How many days can they sustain on the remaining provision?​

Answer»

that no. of days is INVERSELY propotional to the provision for men.   So for 120 men the provision would last for 30days. (given)   Therefore, the provision for 1 men would SUSTAIN for. 120 *30 = 3600 days.   Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days   A.t.q 120*30 = 120*5+125*x   (120*30) - (120*5)= 125x   120(30-5)=125x   120 * 25 = 125x   120 = 5X   x=120/5   x= 24   so the provision would remain for more 24 days.



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