1.

A gas absorbs a photon of 355nm and emits at two wavelengths. If one of the emissions is at 680 nm. The other is at:

Answer»

`743 nm
518nm
1035 nm
325 nm

Solution :`(HC)/(LAMDA)=(hc)/(lamda_(1))+(hc)/(lamda_(2))`
or `1/(lamda)=1/(lamda_(1))+1/(lamda_(2))`
`1/355=1/680+1/(lamda_(2))`
or `1/(lamda_(2))=1/355-1/680=(680-355)/(355xx680)` `1/(lamda_(2))=1.346xx10^(-3):.lamda_(2)=743nm`


Discussion

No Comment Found