1.

A gas at 10^(@)C occupies a volume of 283ml. If it is heated to 20^(@)C keeping the pressure constant, the new volume will be

Answer»

293 ml
283ml
566ml
586ml

Solution :`V_(1) = 283 ml`,
`T_(1) = 273+ 10 = 283 K`
`V_(2) = ?`
`T_(2) = 273 + 20 = 293K`
At constant P,
`( V_(1))/( T_(1)) = ( V_(2))/( T_(2))`
or `V_(2) = ( V_(1)T_(2))/( T_(1))`
`V_(2) = ( 283 xx 293)/( 283) = 293ml`


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