InterviewSolution
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InterviewSolution
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A gas at 300 K has pressure `4 xx 10^(-10) N//m^(2)`. IF `k = 1.38 xx 10^(-23) J//K`, the number of `"molecule"// cm^(3)` is of the order ofA. `10^(5)`B. 10C. `10^(7)`D. `10^(11)` |
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Answer» Correct Answer - A From `PV = n RT = nN(R/N)T = n N kT` `(nN)/(V) = P/(kT) ` = number of `"molecules" //m^(3)` `:.` Number of `"molecules"//m^(3) = (P)/(kT) xx 10^(-6)` `=( 4 xx 10^(-10) xx 10^(-6))/(1.38 xx 10^(-23) xx 300) ~= 10^(5)`. |
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