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A gas at N.T.P. is suddenly compressed to one fourth of its original volume. Ifgamma is supposed to be 3/2 then final pressure is : |
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Answer» <P>4 atmospheres `V_(2)=V//4, P_(2)=?, gamma=3//2` Since `P_(1)V_(1)^(gamma) =P_(2)V_(2)^(gamma)` `therefore P_(2)=P_(1) ((V_(1))/(V_(2))^(gamma))` `P_(2) =1 ((V)/(V//4))^(3//2)` `P_(2)=8` atmosphere Thus, correct choice is (c). |
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