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A gas `(C_(v.m) = (5)/(2)R)` behaving ideally is allowed to expand reversibly and adiabatically from `1` litre to `32` litre. Its initial temperature is `327^(@)C`. The molar enthalpy change (in `J//mol`) for the process is :A. `-1125R`B. `-675`C. `-1575R`D. None of these |
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Answer» Correct Answer - C `(T_(2))/(T_(1))=((V_(1))/(V_(2)))^(gamma-1)` `T_(2)=T_(1).((1)/(32))^((7)/(5)-1)=600.((1)/(2^(5)))^((2)/(5))` `=600(0.5)^(2)=150K` `DeltaH_(m)=(7)/(2)Rxx(150-600)=-1575R` |
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