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A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm. The pressure gauge of cylinder indicates 12 atm at 27^(@)C. Due to sudden fire in the building, its temperature starts rising. At what temperature the cylinder will explode ?

Answer»

Solution :Suppose the CYLINDER will BURST at `T_(2)K`.
When the pressure will increase from 12 ATM to 14.9 atm we have,
`(p_(1)V_(1))/(T_(1)) = (p_(2)V_(2))/(T_(2))""p_(1) = 12 " atm ", T_(1) = (27+273)`
`p_(2) = 14.9` atm, `T_(2) = ?`
Here `V_(1) = V_(2)` as the volume does not change
`THEREFORE T_(2) = (p_(2)T_(1))/(p_(1)) = (14.9 XX 300)/(12)`
= 372.5 K


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