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A gas expands from a volume of `1m^(3)` to a volume of `2m^(3)` against an external pressure of `10^(5)Nm^(-2)`. The work done of the gas will beA. `10^(5)kJ`B. `10^(2)kJ`C. `10^(2)J`D. `10^(3)J` |
Answer» Correct Answer - B `W=PDeltaV=-10^(5)Nm^(-2)xx(2-1)m^(-2)` `=10^(5)Nm=10^(5)J=10^(2)kJ`. |
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