1.

A gas expends from `2 L` to `6L` against a constant pressure of `0.5` atm on absobing `200 J` of heat. Calculate the change in internal energy.

Answer» `Delta U = q+w`
`= 200 J-0.5 atm (62-22)`
`= 200 J-2 L atm`
`= 200 J - 2 xx 101. 3 J ("1 L atm = 101.3 J")`
`= - 2.6 J`


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