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A gas, for which `gamma` is `(4)/(3)` is heated at constant pressure. The percentage of heat supplied used for external work isA. `25%`B. `15%`C. `60%`D. `40%` |
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Answer» Correct Answer - A `(DeltaW)/(DeltaQ)=(nRDeltaT)/(nC_PDeltaT)=(R)/(C_P)=(R)/((gammaR)/((gamma-1)))` `=(gamma-1)/(gamma)=((4)/(3)-1)/((4)/(3))=(1)/(4)=0.25` i.e., `25%` |
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