1.

A gas formed by the action of alcoholic KOH on ethyl iodide, decolourises alkaline KMnO_4 solution. The gas is

Answer»

`CH_4`
`C_2H_6`
`C_2H_4`
`C_2H_2`

Solution :`CH_3CH_2I+KOH(ALC) to CH_2 =CH_2 +KI + H_2O`
`CH_2=CH_2+underset"Alk PINK"(KMnO_4)overset(H_2O)to underset("COLOURLESS")(underset(OH)underset(|)CH_2-underset(OH)underset(|)CH_2+MnO_4)`


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