1.

A gas formed by the action of alcoholic KOH on ethyl iodie, decolourises alkaline KMnO_(4). The gas is

Answer»

`C_(2)H_(6)`
`CH_(4)`
`C_(2)H_(4)`
`C_(2)H_(4)`

SOLUTION :Ethylene is formed by the action of alcoholic KOH on ethyl iodide
`C_(2)H_(5(I+KOH(alc.)toC_(2)H_(4)+KI+H_(2)O`
`C_(2)H_(4)` DECOLOURISES ALKALINE `KMnO_(4)` to form enthylene glycol.
`C_(2)H_(4)+(KMnO_(4)(alk.)) underset(H_(2)O+O) to underset("Ethylene glycol")({:(CH_(2)OH,),(|,),(CH_(2)OH,):}`


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