1.

A gas has a density of 1.2504 g/L at 0^(@)C and a pressure of 1 atm. Calculate the rms, average and the most probable speeds of its molecules at 0^(@)C.

Answer»

Solution :`p = 76 xx 13.6 xx 981 "dynes/cm"^(2)`
`d = 1.2504 g//L = 0.0012504 g//c c`
Now we have,
`C = sqrt((3P)/(d))`
`= sqrt((3 xx 76 xx 13.6 xx 981)/(0.0012504)) = 4.93 xx 10^(4) cm//s`.
`therefore` average SPEED `= 0.9211 xx 4.93 xx 10^(4)`
`= 4.59 xx 10^(4)` cm/s
and most probable speed `= 0.8165 xx 4.93 xx 10^(4)`
`= 4.03 xx 10^(4)` cm/s.
[RMS speed : AV. speed : m.p. speed = 1: 0.9211 : 0.8165]


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