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A gas is allowed to expand at constant temperature from a volume of `1.0 L` to `10.0 L` against an external pressure of `0.50` atm. If the gas absorbs `250 J` of heat from the surroundings, what are the values of `q` and `DeltaE` ? (Given `1 L "atm" =101 J`)A. `{:(q,w,DeltaE),(250J,-455J,-205J):}`B. `{:(q,w,DeltaE),(-250J,-455J,-710J):}`C. `{:(q,w,DeltaE),(250J,455J,710J):}`D. `{:(q,w,DeltaE),(250J,455J,205J):}` |
Answer» Correct Answer - A `q="heat absorbed"=+250 J` `W=-PDeltaV=-0.5"atm"xx(10-1)` `=-4.5 L-"atm"` `=-4.5xx101J=-454.5 J` Now `q=DeltaE-W` `DeltaE=q+W=250-454.5` `=-204.5 J` |
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