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A gas is at 1 atm pressure with a volume `800 cm^(3)`. When `100 J` of heat is supplied to the gas, it expands to `1L` at constant pressure. The change in its internal energy isA. `80 J`B. `- 80 J`C. `20 J`D. `- 20 J` |
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Answer» Correct Answer - A a. Work done by the gas at constant pressure `Delta W = P Delta V` ` =(1 xx 10^(5) Nm^(-2)) (100 - 800) xx 10^(-6) m^(3) = 20 J` `Delta U = Delta Q - Delta W` `Delta U = 100 J - 20 J = 80 J` |
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