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A gas is at 1 atm pressure with a volume `800 cm^(3)`. When `100 J` of heat is supplied to the gas, it expands to `1L` at constant pressure. The change in its internal energy isA. `80 J`B. `-80 J`C. `20 J`D. `-20 J` |
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Answer» Correct Answer - A Work done by the gas, at constant pressure `DeltaW = PDeltaV` `=(1xx10^(5)Nm^(-2))(1000-800)xx10^(-6)m^(3)=20J` `DeltaU = DeltaQ-DeltaW`, so, `DeltaU=100J-20J = 80J`. |
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