1.

A gas is filled in container at pressure P_(0). If the mass of molecules is halved and their rms speed is doubled, then the resultant pressure would be :

Answer»

<P>`2P_(0)`
`4P_(0)`
`(P_(0))/4`
`(P_(0))/2`

Solution :Using, `P=1/3Pv_("rms")^(2)=1/3(mN)/VV_("rms")^(2)`
`thereforePpropmv_("rms")^(2)`
As mis halved `v_("rms")` is doubled P BECOMES TWICE= `2P_(0)`.
Correct CHOICE is (a)


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