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A gas is found to be obeyed the law `p^2V = constant`. The initial temperature and volume are `T_0 and V_0`. If the gas expands to a volume `3 V_0`, then the final temperature becomes.A. `T/(sqrt(3))`B. 3TC. `T/3`D. `Tsqrt(3)` |
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Answer» Correct Answer - D From equation PV=nRT and `P^(2) V=` constant `(T^(2))/V`=constant `T_(2)=sqrt(3)T` |
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