1.

A gas is found to contain 2.34 g of Nitrogen and5.34 g of oxygen. Simplest formula of thecompound is(1) N2O(2) NO(3) N203(4) NO2

Answer»

2.34/14= N = 0.1675.34/16 = O = 0.333

divide moles by least amount of moles

N = 0.167/.167 = 1O = 0.333/.167 = 2

this way it can be found by emperical formula.

formula will be NO2



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