InterviewSolution
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InterviewSolution
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`A` gas is found to obey the law `P^(2)V`= constant. The initial temperature and volume are `T_(0)` and `V_(0^(@))` If the gas expands to a volume `3V_(0)`, thenA. final temperature become `sqrt3 T_(0)`B. internal energy of the gas will increaseC. final temperature becomes `(T_(0))/(sqrt3)`D. internal energy of the gas decrease. |
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Answer» Correct Answer - A::B `P^(2)V=` constant `(n^(2)R^(2)T^(2))/(V^(2)).V=` constant `P=(nRT)/(V)implies(T^(2))/(V)=` constant `(T_(o)^(2))/(V^(o))=(T^(2))/(3V_(o))impliesT=sqrt3T_(o)TalphasqrtV` here `V` increases `:. T` increases hence internal energy increases |
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