1.

A gas is present of 2 atm. What should be in the increase so that the volume of the gas can be decreased to 1//4^(th) of the initial value if the temperature is maintained constant.

Answer»

Solution :PV = constant for a given mass of gas at constant pressure.
`rArr P_(1) V_(1) = P_(2) P_(2)``P_(1) = `2 atm `V_(1) =V`
`V_(2) = V//4` `P_(2) = ?`
Now, `2 xxV = P_(2) xx ( V)/( 4)rArrP_(2) = 8` atm
`:.` Pressue should be increased from 2 to 8 atm
`:.` total INCREASE = 8- 2 == 6 atm


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