1.

A gas is suddenly compressed to `1/4th` of its original volume. Caculate the rise in temperature when original temperature is `27^(@)C. gamma= 1.5`.

Answer» Here, `V_(2)=1/4V_(1)`,
`T_(1)= 27^(@)C= 27+273=300K`,
`gamma=1.5`
`(T_(2)-T_(1))=?`
As `T_(2)V_(2)^(gamma-1)= T_(1)V_(1)^(gamma-1)`
`:. T_(2)=T_(1)((V_(1))/(V_(2)))^(gamma-1)= 300(4)^(1.5-1)= 600K`
`T_(2)-T_(1)= 600-300= 300k= 300^(@)C`


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