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A gas is suddenly compressed to `1/4th` of its original volume. Caculate the rise in temperature when original temperature is `27^(@)C. gamma= 1.5`. |
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Answer» Here, `V_(2)=1/4V_(1)`, `T_(1)= 27^(@)C= 27+273=300K`, `gamma=1.5` `(T_(2)-T_(1))=?` As `T_(2)V_(2)^(gamma-1)= T_(1)V_(1)^(gamma-1)` `:. T_(2)=T_(1)((V_(1))/(V_(2)))^(gamma-1)= 300(4)^(1.5-1)= 600K` `T_(2)-T_(1)= 600-300= 300k= 300^(@)C` |
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