InterviewSolution
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InterviewSolution
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A gas is undergoing an adiabatic process. At a certain stage A, the values of volume and temperature `(V_(0), T_(0))`. From the details given in the graph, find the value of adiabatic constant `gamma` A. `(V_(0))/(T_(0) tan theta) + 1`B. `(V_(0) tan theta)/(T_(0) + 1`C. `(V_(0) tan^(2) theta)/(T_(0)) + 1`D. `(V_(0))/(T_(0)) + tan theta` |
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Answer» Correct Answer - A We have, for an adiabatic process, in relation wiht temperature and volume `TV^(gamma-1)` = constant Differentiating with respect to `T` `V^(gamma-1).1+T.(gamma-1)V^(gamma-1)=(V_0)/(T_(0)tan theta)` `gamma = (V_0)/(T_0 tan theta) + 1`. |
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