1.

A gas mixture contains 50% helium and 50% methane by volume. What is the percent by weight of methane in the mixture?

Answer»

`19.97%`
`20.05%`
`50%`
`80.03%`

Solution :Equal volumes contain equal NUMBER of moles.
Hence, MOLAR ratio of `He:CH_(4)=1:1`
`therefore" Ratio by weight "=4:16=1:4`
`therefore CH_(4)` present by weight`=(4)/(5)xx100=80%`


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