1.

A gas mixture contains 50% helium and 50% methane by volume. What is the percent by weight of methane in the mixture.

Answer»

`19.97%`
`20.05%`
`50%`
`80.03%`

Solution :Solution CONTAIN `He +CH_(4)`
Their mol. `wt = 4+16 = 20`
`%`wt of `CH_(4) = (" wt of " CH_(4))/(" TOTAL wt") xx 100 = 16/20 xx 100 = 80.0%`


Discussion

No Comment Found

Related InterviewSolutions