1.

A gas mixture of CH_(4) and C_(3)H_(6) undergo complete cracking into C_(s) and H_(2)(g). The total mass of H_(2) (g) produced is 42 gm. If the total volume of the initial gas mixture at 1 atm and 0 .^(@)C is 224 litre then mole % of CH_(4) in original mixture is -

Answer»

`10%`
`20%`
`90%`
`80%`

SOLUTION :MOLE of mixture `= (224)/(22.4) = 10`
`CH_(4) RARR C (s) + 2H_(2) (g)`
`{:(CH_(4),rarr,C (s),+ 2H_(2) (g),),(x "mole",,,2x "mole",),(C_(3)H_(6),rarr,3C (s),+ 3H_(2) (g),),((10 - x) "mole",,,3 (10 - x) "mole",):}`
`[2x + 3 (10 - x )] = 21`
`2x + 30 - 3X = 21`
`x = 9` mole
`%` mole of `CH_(4) = (9)/(10) xx 100 = 90%`


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