InterviewSolution
Saved Bookmarks
| 1. |
A gas occupies `2L` at `STP`. It is provided `300J` heat so that it volume becomes `2.5L` at `1atm`. Caluclate the change in its internal enegry. |
|
Answer» Work done `=- P xx DeltaV = 1 xx (2.5 - 2.0)` `=- 0.5 L atm` Therefore, work is carried out at constant `P` and thus irreversible. `=- (0.5 xx 1.987xx4.184)/(0.0821)J =0.5 xx 101.328J` `=- 50.631J` From the first law of thermodynamics, `:. q = DeltaU - w` `300 = DeltaU +50.63:. DeltaU = 249.37J` |
|