A gas take part in two thermal processes in which it is heated from the same initial state to the same final temperature. The processes are shown on the `P-V` diagram by straight lines `1 rarr 3 ` and `1 rarr 2` A. `W_(13)gt W_(12)`B. `W_(12)gt W_(13)`C. `W_(13)= W_(12)`D. None of above

A gas take part in two thermal processes in which it is heated from th

1.	A gas take part in two thermal processes in which it is heated from the same initial state to the same final temperature. The processes are shown on the `P-V` diagram by straight lines `1 rarr 3 ` and `1 rarr 2` A. `W_(13)gt W_(12)`B. `W_(12)gt W_(13)`C. `W_(13)= W_(12)`D. None of above
Answer» Correct Answer - A Since the temperature remains constant, `Delta T=0` Now `W_(12)=(1)/(2) (P_(1)+P_(2))(V_(2)-V_(1))` `W_(13)=(1)/(2) ( P_(1)+P_(3))(V_(3)-V_(1))` `W_(12)-W_(13)=(1)/(2)[P_(1)(V_(2)-V_(3))+(P_(3)-P_(1))]lt0` `W_(13)gtW_(12), Q_(13)gtQ_(12)`

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A gas take part in two thermal processes in which it is heated from the same initial state to the same final temperature. The processes are shown on the `P-V` diagram by straight lines `1 rarr 3 ` and `1 rarr 2` A. `W_(13)gt W_(12)`B. `W_(12)gt W_(13)`C. `W_(13)= W_(12)`D. None of above

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