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A gaseous alkane was exploded with oxygen. The volume of `O_(2)` for complete combustion to `CO_(2)` formed was in the ratio of `7:4`. The molecular formula of alkane is:A. `CH_(4)`B. `C_(2)H_(6)`C. `C_(3)H_(6)`D. `C_(4)H_(10)` |
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Answer» Correct Answer - B `C_(n)H_(2n+2)+[n+(n+1)/(2)]O_(2)rarrnCO_(2)+(n+1)H_(2)O` `("Volume of" O_(2) "used")/("Volume of" CO_(2) "formed")=(7)/(4)` `(n+(n+2)//2)/(n)=(7)/(4)` `:. n=2` and alkane is `C_(2)H_(6)`. |
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