1.

A gaseous hydrocarbon gives upon combustion, 0.72 g of water and 3.08 g of CO_(2). The empirical formula of the hydrocarbon is

Answer»

`C_(2)H_(4)`
`C_(3)H_(4)`
`C_(6)H_(5)`
`C_(7)H_(8)`

Solution :`18g H_(2)O` CONTAINS `2g H`
`:. 0.72 g H_(2)O` contains `0.08 g H`
`44 g CO_(2)` contains `12 g C`
`:. 3.08 g CO_(2)` contains `0.84 g C`
`:. C : H = (0.84)/(12): (0.08)/(1) = 0.07:00.08 = 7 : 8`
`:. ` Empirical formula `= C_(7)H_(8)`.


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