InterviewSolution
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InterviewSolution
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A gaseous hydrocarbon requires 6 times its own volume of O_(2) for complete oxidation and produces 4 times its volume of CO_(2). What is its formula ? |
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Answer» Solution :The balanced EQUATION for combustion `C_(x) H_(y)+(x+(y)/(4))O_(2) rarr xCO_(2) +(y)/(2) H_(2)O` 1 VOLUME `(x+(y)/(4))` volume `therefore x+(y)/(4)=6` (by equation) or 4x+y=24 Again x=4 since evolved `CO_(2)` is 4 times that of hydrocarbon `therefore 16 +y=24" or "y=8 therefore` formula of hydrocarbon `C_(4)H_(8)` |
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