1.

A gaseous mixture consists of 16g of helium and 16 g of oxygen. The ratio (C_(p))/(C_(v)) of the mixture is :

Answer»

<P>`1 cdot 54`
`1 cdot 62`
`1 cdot 4`
`1 cdot 59`

Solution :We know that `C_(21)=(n_(1)Cv_(1)+n_(2)Cv_(2))/(n_(1)+n_(2))`
and `C_(P) =(n_(1)CP_(1)+n_(2)CP_(2))/(n_(1)+n_(2))`
`therefore (C_(p))/(C_(v))=(4xx(5)/(2) R+(1)/(2)xx(7)/(2) R)/(4xx(3)/(2)R+(1)/(2)xx(5R)/(2))`
`therefore` Correct CHOICE is (b).


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