1.

A gaseous mixture contain 50% He and 50% CH_4by volume. What is the percent by weight of CH_4in the mixture ?

Answer»

0.1997
0.2005
0.5
0.75

Solution :`("VOL. of He")/("vol. of " CH_4) = 50/50 = 1/1 `
` ("no. of MOLECULES of He")/("no. of molecules of " CH_4) = 1/1`
`(" mass of He")/("mass of " CH_4) = 4/16 = 1/4`
% of `CH_4` in mixture `= (4 xx 100)/(5) = 80.03%`


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