1.

A gaseous substance ABhas a radioactive element A with a half life of 2 days. The gaseous substance decomposes to A_((g)) and B_((g)) in a closed container and an equilibrium gets established rapidly withina fraction of second . The substance to which A decays into is non gaseous and does not effect volume of the container. If equilibrium constant is 9 atm then calculate partial pressure of AB after 4 days if initial pressure of AB taken was 4 atm.

Answer»

`(1)/(4)` atm
`(1)/(2)` atm
1atm
2 atm

Solution :`{:(AB(g),hArr,A(g),+,B(g),K_(P)=9 "atm",),(4 "atm",,0,,0,,),(4 "atm"-x,,x,,x,,),(,,K_(P)=(x xxx)/(4-x)=9,,,,):}`
x=3, -12 x can't be -12
Partial pressure of ABat equilibrium=1 atm
Now after 4 day (TWO half LIFE)the pressure of AB willbecame =`(1)/(4) atm`]


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