1.

A Ge specimen is doped with Al. The concentration of acceptor atoms is ~ 10^(21) m^(-3). Given that the intrinsic concentration of electron-hole pairs is ~ 10^(19) m^(-3) . The concentration of electrons in the specimen is

Answer»

`10^(17) m^(-3)`
`10^(15) m^(-3)`
`10^(4) m^(-3)`
`10^(2) m^(-3)`

SOLUTION :As `n_(i) = 10^(19) m^(-3) and n_(h)= 10^(21) m^(-3) and n_(E).n_(h) = n_(i)^(2) RARR n_(e) = (n_(i)^(2))/(n_(h)) = ((10^(19))^(2))/(10^(21)) = 10^(17) m^(-3)`


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