A Ge specimen is doped with Al. The concentration of acceptor atoms is ~10^(21) atoms/ m^3 . Given that the intrinsic concentration of electron hole Paris is ~10^(19)//m^3 , the concentration of electrons in the specimen is :

A Ge specimen is doped with Al. The concentration of acceptor atoms is

1.	A Ge specimen is doped with Al. The concentration of acceptor atoms is ~10^(21) atoms/ m^3 . Given that the intrinsic concentration of electron hole Paris is ~10^(19)//m^3 , the concentration of electrons in the specimen is :
Answer» `10^(17)//m^3` `10^(15)//m^3` `10^(4)//m^3` `10^2//m^3` Solution :`n_i^2=n_exxn_n` `:. n_e =(n_i^2)/(n_h)=(10^(19))^2/10^(21)=10^(17)//m^3`

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A Ge specimen is doped with Al. The concentration of acceptor atoms is ~10^(21) atoms/ m^3 . Given that the intrinsic concentration of electron hole Paris is ~10^(19)//m^3 , the concentration of electrons in the specimen is :

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