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A general solution of `tan^(2) theta+ cos 2 theta=1` is `(n in Z)`A. `n pi-pi/4`B. `2npi+pi/4`C. `npi+pi/4`D. `n pi` |
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Answer» Correct Answer - A::C::D We have `tan^(2) theta=1-cos 2 theta=2 sin^(2) theta` or `cosec^(2) theta tan^(2) theta=2` or `(1+cot^(2) theta) tan^(2) theta=2` or `tan^(2) theta+1=2` or `tan^(2) theta=1` or `tan theta = pm 1` `rArr theta=n pi pm pi/4, n in Z` Moreover, `tan^(2) theta=2 sin^(2) theta` `rArr sin^(2) theta=0rArr theta = npi` |
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