1.

A geostatationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R being the radius of the earth. The time peiod of another satellite in hours at a height of 2R from the surface of the earth is :

Answer»

`(6)/(sqrt(2))`
5
10
`6sqrt(2)`

SOLUTION :`(T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3//2)=((3R)/(6R))^(3//2)=((1)/(2))^(3//2)`
`=(1)/(2sqrt(2))`
`THEREFORE T_(2)=(1)/(2sqrt(2))xx24=6sqrt(2)`
Thus correct choice is (d).


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