InterviewSolution
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InterviewSolution
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(a) Give chemical tests to distinguish between the following compounds (One test in each case) : (i) Aniline and ethyl amine. ""(ii) Methyl amine and dimethyl amine. (b) How will you convert aniline to sulphanilic acid ? |
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Answer» Solution :(a) (i) Distinction between aniline and ETHYL amine : Ethyl amine reacts with nitrous ACID to form ALIPHATIC diazonium salt which being unstable liberates nitrogen gas and alcohol. Aniline reacts with nitrous acid at low temperature (273-278 K) to form diazonium salts. (ii) Distinction between METHYL amine and dimethyl amine : `underset(underset("(PRIMARY amine)")("Methyl amine"))(CH_(3)NH_(2))""underset(underset("(Secondary amine)")("Dimethyl amine"))(CH_(3)-NH-CH_(3))` `CH_(3)NH_(2)` reacts with benzene sulphonyl chloride to form N-methylbenzene sulphonamide which is soluble in alkali. `CH_(3)NHCH_(3)` reacts with benzene sulphonyl chloride to form N, N-Dimethyl sulphonamide which is insoluble in alkali. This is how the two compounds can be distinguished. (b) Aniline to sulphanilic acid : 
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