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a. Give the expression showing the relation between energyand momentum of a photon. b. "de-Broglie wavelength supports Bohr's model of stationary orbits." Comment on this statement. c. Is there any difference between the wavelength of the radiation and d-Broglie wavelength of a photon of that radiation? Explain. |
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Answer» Solution :a. Momentum of PHOTON `=(hupsilon)/(c )` B. Bohr orbit condition, `mvr=(nh)/(2pi)` i.e., `pr=(nh)/(2pi)` taking `(h)/(p)=(2pi r)/(N)=(L)/(n)`. This suggests that `lambda=(L)/(n)` or total length of the orbit is n times de Broglie.s wavelength. c. No. Wavelength of RADIATION `lambda=(c )/(upsilon)` de Broglie.s wavelength `lambda=(h)/(p)=(c )/(upsilon)` |
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