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A given coin has a mass of 3.0 grams Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other .Assume that the coin is entirely made of ._29Cu^63 atoms of mass =62.92960 u. Given Avogadro number = 6.023xx10^23, mass of proton m_p = 1.00727u and mass of neutron m_n=1.00866 u. |
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Answer» SOLUTION :Given : - No of atoms in a 3 gram COIN `=(6.023xx10^23xx3)/63` `=2.868xx10^22` Each atom of copper containing 29 protons and 34 neutrons . `therefore`Mass defect `Deltam=[Zm_p +(A -Z)m_n ]-M` `Deltam=[29xx1.00727+(63-29)1.00867]-62.98960` `Deltam=0.57601`u Total mass deject for all the atoms `=E xx Deltam` `=0.57601xx2.868xx10^22` `=1.652xx10^22` u 1u=931 MEV Nuclear energy required= `1.6252xx10^22xx931=1.528xx10^22` MeV |
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