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A given coin has a mass of 3.0g . Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other . For simplicity,assume that the coin is entirely made of ._(29)^(63)Cu atoms (of mass 62.92960 u) |
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Answer» Solution :Mass defect in each copper nucleus `Delta m = 29 m_(p) + 34 m_(n) - M_(Cu)` `= (29 xx 1.00727 ) + (34 xx 1.00866) -62.929 60` `Delta m = 0.57567` U Energy required to separate all neutrons and protons in one nucleus (is binding energy) `= Delta mxx 931.5 "MeV"` `E_(b) = 0.57567 X 931.5 = 536.2 "MeV"` Number of atoms in the copper COIN : `N= (6.023 xx 10^(23) xx 3)/( 63) = 2.868 xx 10^(22)` `therefore` Total energy required to separate all neutrons and protons in the coin `E_(b) xx N ` `536.2xx 2.868 xx 10^(22) = 1.538 xx 10^(25) "MeV"` (with unit) |
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