1.

A given coin has a mass of 3.0g . Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other . For simplicity,assume that the coin is entirely made of ._(29)^(63)Cu atoms (of mass 62.92960 u)

Answer»

Solution :Mass defect in each copper nucleus
`Delta m = 29 m_(p) + 34 m_(n) - M_(Cu)`
`= (29 xx 1.00727 ) + (34 xx 1.00866) -62.929 60`
`Delta m = 0.57567` U
Energy required to separate all neutrons and protons in one nucleus (is binding energy)
`= Delta mxx 931.5 "MeV"`
`E_(b) = 0.57567 X 931.5 = 536.2 "MeV"`
Number of atoms in the copper COIN :
`N= (6.023 xx 10^(23) xx 3)/( 63) = 2.868 xx 10^(22)`
`therefore` Total energy required to separate all neutrons and protons in the coin
`E_(b) xx N `
`536.2xx 2.868 xx 10^(22) = 1.538 xx 10^(25) "MeV"` (with unit)


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