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(a) Given n resistores each of resistance R. how will you combine them to get the (i) maximum (ii) minimum effective resistance? (b) Given the resistances of 1 Omega, 2 Omega, 3 Omega. how will be combine them to get an equivalent resistance of (i) (11//3) Omega (ii) (11//5) Omega, (iii) 6 Omega, (iv) (6//11) Omega ? (c ) Determine the equivalent resistance of networks shown in |
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Answer» Solution :When given resistances are all connected in series, equivalent RESISTANCE is maximum. here, `R_(MAX) =R_(S)= nR ` When given resistances are all connected in parallel, equivalent resistance is MINIMUM. Here, `R_(MIN) = R_(p)= (R)/(N) ` Required ratio = `(R_(max))/(R_(min)) = (nR)/((R)/(n)) = n^(2)` |
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