1.

A given sample of AlCl_3contains 6.02 xx 10^20Al^(3+)ions. The moles of Cl^(-1)ions are :

Answer»

`1.0 xx 10^(-3)`
`3.0 xx 10^(-3)`
`3.0 xx 10^3`
`0.33 xx 10^(-3)`

SOLUTION :No. of `CL^(-)` IONS = ` 3 xx 6.02 xx 10^20`
Moles of `Cl^(-)` ions
` = (3 xx 6.02 xx 10^20)/(6.02 xx 10^23) = 3 xx 10^(-3)`


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