1.

A given sample of milk turns sour at room temperature (27^(@) C) in 5 hours . In a refrigerator at -3^(@) C , it can be stored 10 times longer . The energy of activation for the souring of milk is

Answer»

`2.303 xx 10 R kJ * mol^(-1)`
`2.303 xx 5 R kJ* mol^(-1)`
`2.303 xx 3 R kJ * mol^(-1)`
`2.303 xx 2.7 R kJ* mol^(-1)`

SOLUTION :RATE of souring of milk at `27^(@)C` is 10 times faster than at `-3^(@) C` .
HENCE , `(k_(300))/(k_(270)) = 10 , T_(1) = 270 K , T_(2) = 300 K`
`E_(a) = 2.303 R ((T_(1) T_(2))/(T_(2) - T_(1))) LOG (k_(300))/(k_(270))`
`E_(a) = 2.303 R ((270 xx 300)/(300 - 270)) log 10`
`E_(a) = 2.303 R (2. 7 xx 10^(3)) J mol^(-1)`
`E_(a) = 2.303 xx 2.7 R kJ mol^(-1)`


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